# How do you simplify (x^3-27)/(x^3+3x^2+9x)?

Nov 6, 2016

$= \frac{x - 3}{x}$

#### Explanation:

Before you can simplify an algebraic fraction such as this one, you should find the factors first.

$\left(\left(\text{difference of cubes")rarr)/(("common factor of x}\right) \rightarrow\right) \frac{{x}^{3} - 27}{{x}^{3} + 3 {x}^{2} + 9 x}$

=((x-3)cancel((x^2+3x+9)))/(xcancel((x^2+3x+9))

$= \frac{x - 3}{x}$