Question

How do you simplify `(x^3-27)/(x^3+3x^2+9x)`?

Answer 1

`= (x-3)/x`

Explanation:

Before you can simplify an algebraic fraction such as this one, you should find the factors first.

`(("difference of cubes")rarr)/(("common factor of x")rarr) (x^3 -27)/(x^3+3x^2+9x)`

`=((x-3)cancel((x^2+3x+9)))/(xcancel((x^2+3x+9))`

`= (x-3)/x`