# How do you simplify (-x)^3 (-3x^2)^2?

May 8, 2016

$- {x}^{3} \times 9 {x}^{4} = - 9 {x}^{7}$
${\left(- x\right)}^{3} = - {x}^{3} \text{ }$ NB - an odd number of negatives $\Rightarrow$ neg
${\left(- 3 {x}^{2}\right)}^{2} = + 9 {x}^{4} \text{ }$ Square the -3 and the ${x}^{2}$
$\therefore - {x}^{3} \times 9 {x}^{4} = - 9 {x}^{7}$