# How do you simplify (x^(3/4)yz^(-1/3))/(x^(1/4)z^(2/3))?

${x}^{\frac{1}{2}} y {z}^{- 1}$ or $\frac{{x}^{\frac{1}{2}} y}{z}$
${x}^{\frac{3}{4}} / {x}^{\frac{1}{4}} = {x}^{\frac{3}{4} - \frac{1}{4}} = {x}^{\frac{1}{2}}$
${z}^{- \frac{1}{3}} / {z}^{\frac{2}{3}} = {z}^{- \frac{1}{3} - \frac{2}{3}} = {z}^{- \frac{3}{3}} = {z}^{- 1}$