How do you simplify  (x^(-3/8) y^(1/4))^16?

Jun 19, 2018

${y}^{4} / {x}^{6}$

Explanation:

use the rule ${\left({a}^{n}\right)}^{m} = {a}^{n \cdot m}$

${\left({x}^{- \frac{3}{8}} {y}^{\frac{1}{4}}\right)}^{16}$

${x}^{- \frac{3}{8} \cdot 16} {y}^{\frac{1}{4} \cdot 16}$

${x}^{- 6} {y}^{4}$

Now use the rule ${a}^{-} n = \frac{1}{a} ^ n$

${y}^{4} / {x}^{6}$