How do you simplify #(x^3y^2z^6)/(z^5x^2y)#?

1 Answer

Answer:

#xyz#

Explanation:

When you divide exponents with the same base, you simply subtract the exponents. So subtract the indices of each variable at a time:
#x^3divx^2 =x " " (3-2=1)#
#y^2divy=y " "(2-1=1)#
#z^6divz^5=z" " (6-5=1)#

This was pretty easy since there were no negatives.

(You always subtract the top number/numerator minus bottom number/denominator)

Your answer is

#xyz#.