How do you simplify x^4y^3*(2y^2)^0 and write it using only positive exponents?

May 27, 2017

${x}^{4} {y}^{3}$

Explanation:

$\text{using the "color(blue)"law of exponents}$

$\textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{{a}^{0} = 1} \textcolor{w h i t e}{\frac{2}{2}} |}}}$

$\Rightarrow {x}^{4} {y}^{3} \times {\left(2 {y}^{2}\right)}^{0}$

$= {x}^{4} {y}^{3} \times 1$

$= {x}^{4} {y}^{3}$