# How do you simplify (x^-6)/(x^4y^0)?

May 19, 2015

Let's remember $3$ important exponent laws:

• ${a}^{0} = 1$

• ${a}^{n} / {a}^{m} = {a}^{n - m}$

-${a}^{-} n = \frac{1}{a} ^ n$

Using the first, we can "cancel" $y$:

${x}^{-} \frac{6}{{x}^{4} \cdot 1}$

Using the second, we combine the exponents:

${x}^{- 6 - 4} = {x}^{-} 10$

Finally, we know that

${x}^{-} 10 = \frac{1}{x} ^ 10$