How do you simplify #(x²-7x+6)/ (x²-1) div(2x²-12x)/(x+1)#?

1 Answer
Aug 19, 2016

Answer:

#1/(2x)#

Explanation:

Start off with a question involving algebraic fractions by factoring wherever possible.

#(x²-7x+6)/ (x²-1) div(2x²-12x)/(x+1) " change " div" to "xx " by reciprocal"#

#((x-6)(x-1))/((x+1)(x-1)) xx ((x+1))/(2x(x-6))#

#(cancel((x-6))cancel((x-1)))/(cancel(x+1)cancel(x-1)) xx (cancel(x+1))/(2xcancel((x-6)))" cancel like factors"#

=#1/(2x)#