How do you simplify #(x-8)^2/12 ÷ (12x - 96)/144 #?

1 Answer
Jul 15, 2015

Answer:

#(x-8)^2/12 div (12x-96)/144 = x-8#
#color(white)("XXXX")##color(white)("XXXX")##color(white)("XXXX")##color(white)("XXXX")#assuming #x!= 8#

Explanation:

#(x-8)^2/12 div (12x-96)/144#

#=(x-8)^2/12 xx 144/(12x-96)#

#= ((x-8)(x-8))/12 xx (12*12)/(12*(x-8))#

#= ((x-8)cancel((x-8)))/cancel(12) xx (cancel(12)*cancel(12))/(cancel(12)*cancel((x-8)))#

#=x-8#