How do you simplify #x^(n+2) div x^(n-3)#?

Question

1325 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-20T11:43:34

#x^5#

#color(blue)(x^(n+2)-:x^(n-3)#

Remember the law of exponents #color(brown)(x^y-:x^z=x^(y-z)#

#:.x^(n+2)-:x^(n-3)=x^((n+2)-(n-3))#

#rarrx^(n+2-n+3)#

Gather up the like terms

#rarrx^((n-n)+2+3)#

#rarrx^(2+3)#

#color(green)(rArrx^5#