How do you sketch one cycle of #y=4sin3x#? Trigonometry Graphing Trigonometric Functions Translating Sine and Cosine Functions 1 Answer sankarankalyanam Oct 10, 2017 #y=4sin 3x# graph{4sin(3x) [-10, 10, -5, 5]} Explanation: #y=4sin3x# #x=0,y=0# #x=(pi/18), y=2# #x=(pi/12), y=2sqrt2# #x=(pi/9), y=2sqrt3# #x=(pi/6), y=4# #x=(pi/3), y=0# Answer link Related questions How do you graph sine and cosine functions when it is translated? How do you graph #y=sin ( x -frac{\pi}{2} )#? How do you draw a sketch of #y = 1 + cos (x - pi)# How do you shift and graph #y=-3+sinx#? How do you graph #y=3sin(1/3x+ pi/2)-2#? How do you graph #1/2sin(x-pi)#? How do you graph #-sinx+2#? How do you graph #y=3sin(1/2)x#? How do you graph #y=-2cos((pix)/3)#? How do you graph #y = (1/2)sin(x - pi)#? See all questions in Translating Sine and Cosine Functions Impact of this question 2538 views around the world You can reuse this answer Creative Commons License