# How do you sketch the angle (11pi)/6 in standard position?

it's in the standard form. When we are in interval: $\left[0 , 2 \pi\right]$
if the interval stands $\left[- \pi , \pi\right]$ then $\frac{11 \pi}{6} = - \frac{\pi}{6}$
$\textcolor{b l u e}{- \frac{\pi}{6}}$ and $\textcolor{red}{\frac{11 \pi}{6}}$