# How do you sketch the angle 4 in standard position?

$\pi \approx 3.14$ so the terminal side of$4$ is past the negative $x$-axis.
$\frac{3 \pi}{2} = \frac{3}{2} \cdot \pi \approx \frac{3}{2} \cdot 3 = 4.5$ so the terminal side of $4$ is not in the fourth quadrant.
If you want to be a little more precise, note that the $\frac{\pi}{4}$ angle in Quadrant 3 is $\frac{5 \pi}{4} \approx \frac{15}{4} = 3.75$, so the terminal side of $4$ is between those of $\frac{5 \pi}{4}$ and $\frac{3 \pi}{2}$