How do you sketch the graph of #y=2 - sin ((2πx)/3)#?

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Answer 1 · 2018-07-27T03:27:22

See graph and details.

#y = 2 - sin ((2pix)/3) in ( 2, 2 ) + ( -1, 1 ) = ( 1, 3 )#

Amplitude of this sine wave #= abs ( - 1 ) = 1#.

Period = ( 2pi )/((2pi)/3) = 3#

Now see the wave,, with these depicted thereupon, for one period

#x in [- 1.5, 1.5 ]#:

graph{(y-2+sin(2/3pix))(y-1)(y-2)(y-3)(x^2-2.25)=0[-4 4 0 4]}

Observe axis of the wave #y = 2#.