How do you sketch the graph of #y=sin (x/2) #?

1 Answer
Mar 29, 2017

Use the parent function #y = sin x# with period #= 4pi# instead of #2pi#

Explanation:

Parent function is #y = sin x# with period = #2 pi#

#x/2 = 1/2x# changes the period. Period #= (2pi)/(1/2) = 4pi#

Divide the period into #4# sections:
#x = 0, x = pi, x = 2 pi, x = 3pi, x = 4pi#

#(0,0)# is an #x#-intercept
#(pi, 1)~~(3.14, 1)# is a maximum
#(2pi, 0)~~(9.4, 0)# is an #x#-intercept
#(3pi, -1)~~(9.4, -1)# is a minimum
#(4pi, 0)~~(12.6, 0)# is an #x#-intercept

graph{sin (x/2) [-10, 10, -5.21, 5.21]}