How do you solve #0=4x^2 + 16x + 15#?

1 Answer
Aug 16, 2015

Answer:

Solve y = 4x^2 + 16x + 15 (1)

Ans: -3/2 and -5/2

Explanation:

I use the new Transforming Method (Google Yahoo Search)
Transformed equation# y' = x^2 + 16x + 60.# (2)
Factor pairs of 60 --> ...(4, 15)(5, 12)(6, 10). This sum is 60 = b. Then, the 2 real roots of (2) are: -6 and -10.
Back to original equation (1), the 2 real roots are: #x1 = -6/4 = -3/2#, and #x2 = -10/4 = -5/2#.