# How do you solve 0=4x^2 + 16x + 15?

Aug 16, 2015

Solve y = 4x^2 + 16x + 15 (1)

Ans: -3/2 and -5/2

#### Explanation:

I use the new Transforming Method (Google Yahoo Search)
Transformed equation$y ' = {x}^{2} + 16 x + 60.$ (2)
Factor pairs of 60 --> ...(4, 15)(5, 12)(6, 10). This sum is 60 = b. Then, the 2 real roots of (2) are: -6 and -10.
Back to original equation (1), the 2 real roots are: $x 1 = - \frac{6}{4} = - \frac{3}{2}$, and $x 2 = - \frac{10}{4} = - \frac{5}{2}$.