How do you solve $0.5 = 4.1 x - 2 (1.3 x - 4)$ $0.5=4.1x-2(1.3x-4)$ ?

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Answer 1 · 2018-05-15T12:32:37

$x = - 5$ $x=-5$

$0.5 = 4.1 x - 2.6 x + 8$ $0.5=4.1x-2.6x+8$ (double negatives cancel out)
$- 7.5 = 1.5 x$ $-7.5=1.5x$
$x = - 5$ $x=-5$

Answer 2 · 2018-05-15T12:33:50

Expand le brackets

$0.5 = 4.1 x - 2.6 x + 8$ $0.5=4.1x-2.6x+8$

Transfer 0.5 and solved $x$ $x$
$- 1.5 x = 7.5$ $-1.5x=7.5$

Multiply both sides by 10
$- 15 x = 75$ $-15x=75$

Transfer 15
$x = - \frac{75}{15}$ $x=-75/15$

$x = - 5$ $color(Red)(x=-5$

How do you solve 0.5=4.1x-2(1.3x-4)0.5=4.1x−2(1.3x−4)0.5=4.1x-2(1.3x-4)?