How do you solve #0.5(x-12) =4#?

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Answer 1 · 2016-03-02T17:40:29

#x= 20#

#(0.5) (x-12) = 4#

Here, #color(blue)(0.5) # is multiplied with both terms within the bracket.

#color(blue)((0.5)) xx (x) + color(blue)((0.5)) xx (-12) = 4#

#0.5x -6= 4#

#0.5x = 4+6#

#0.5x = 10#

#x= 10/(0.5)#

#x= 100/(5)#

#x= 20#