How do you solve #0\leq 4 x - 3 \leq 1 1#?
1 Answer
Feb 26, 2017
Explanation:
We want to
#color(blue)"isolate"# x in the middle interval and have numeric values at the 2 other intervals.add 3 to ALL parts.
#0+3<=4xcancel(-3)cancel(+3)<=11+3#
#rArr3<=4x<=14# divide ALL parts by 4
#3/4<=(cancel(4) x)/cancel(4)<=14/4#
#rArr3/4<=x<=7/2" is the solution"#
