How do you solve 0 = x^2 + 5x + 6?

May 26, 2015

Since ${x}^{2} + 5 x + 6$ can be factored as
$\left(x + 1\right) \left(x + 5\right)$

$0 = {x}^{2} + 5 x + 6$
is equivalent to
$\left(x + 1\right) \left(x + 5\right) = 0$

which implies
either $\left(x + 1\right) = 0$ or $\left(x + 5\right) = 0$

So
$x = - 1$ or $x = - 5$