How do you solve .05(1.15)^x = 5.05(1.15)x=5? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer dani83 Sep 2, 2015 x = log_1.15 100 x=log1.15100 Explanation: log a^n = n log a logan=nloga log_a b = log_c b/log_c a logab=logcblogca 0.05(1.15)^x = 5 0.05(1.15)x=5 1.15^x = 100 1.15x=100 xlog 1.15 = log 100 xlog1.15=log100 x = log_1.15 100 x=log1.15100 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=819x−4=81? How do you solve logx+log(x+15)=2logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 22log4(x+7)−log4(16)=2? How do you solve 2 log x^4 = 162logx4=16? How do you solve 2+log_3(2x+5)-log_3x=42+log3(2x+5)−log3x=4? See all questions in Logarithmic Models Impact of this question 3866 views around the world You can reuse this answer Creative Commons License