Question

How do you solve `(1.011)^x=2`?

Answer 1

63,36, nearly.

Explanation:

`log (a^n)=- n log a`.
Equating logarithms, x log 1,011 = log 2.
So,`x = log 2 / log 1.011` = 63.36, nearly.

Check:`1.011^63.36` = 2.000015, nearly 2.000, rounded to 4-sd..