How do you solve #1 / (1+x) - 1 / (2+x) = 1/4#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer 冠廷 李. Jun 20, 2016 #x=(-3+-sqrt17)/2# Explanation: first the denominator shouldn't be 0 so #x!=-1 and -2# #1/(x+1)-1/(x+2)=1/4# #((x+2)-(x+1))/((x+1)(x+2))=1/4# #(x+1)(x+2)=4# #x^2+3x=2# #x^2+3x+9/4=2+9/4# #(x+3/2)^2=17/4# #x+3/2=+-sqrt17/2# #x=(-3+-sqrt17)/2# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 3077 views around the world You can reuse this answer Creative Commons License