How do you solve #-1+11=\frac{1}{3}x#?

2 Answers
Jan 16, 2018

#x=30#

Explanation:

#"note that "1/3x=x/3#

#-1+11=x/3#

#rArr10=x/3#

#"multiply both sides by 3"#

#(3xx10)=cancel(3)xxx/cancel(3)#

#rArrx=30" is the solution"#

Jan 16, 2018

x = 30

Explanation:

-1 + 11 = #1/3x#
10 = #1/3x#
Multiply each side by 3
#10*3= 3*1/3x#
# 30 = (1cancel3)/(cancel3)x#
# 30 = x#