How do you solve #1/2 [(10-g) + (-6 +3g)]#?

1 Answer
Apr 17, 2016

Answer:

#13/2g-3#

Explanation:

The structure of this question is to test that you understand the consequence of #+(-6+3g)#. Which is:

#color(brown)(+(-6+3g))color(blue)(->-6+3g)#

Think of it as: #(+1)(-6+3g)# where everything in side the brackets is multiplied by #(+1)#

'~~~~~~~~~~~~~~~~~ Something to think about ~~~~~~~

It would be a different matter if you had #-(-6+3g)#
Consider it as #(-1)(-6+3g)# where everything inside the brackets is multiplied by (-1) giving: #+6-3g#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Solving the question")#

Write as #1/2[10g-6+3g]#

#1/2[13g-6]#

#13/2g-3#