# How do you solve 1/2 [(10-g) + (-6 +3g)]?

Apr 17, 2016

$\frac{13}{2} g - 3$

#### Explanation:

The structure of this question is to test that you understand the consequence of $+ \left(- 6 + 3 g\right)$. Which is:

$\textcolor{b r o w n}{+ \left(- 6 + 3 g\right)} \textcolor{b l u e}{\to - 6 + 3 g}$

Think of it as: $\left(+ 1\right) \left(- 6 + 3 g\right)$ where everything in side the brackets is multiplied by $\left(+ 1\right)$

'~~~~~~~~~~~~~~~~~ Something to think about ~~~~~~~

It would be a different matter if you had $- \left(- 6 + 3 g\right)$
Consider it as $\left(- 1\right) \left(- 6 + 3 g\right)$ where everything inside the brackets is multiplied by (-1) giving: $+ 6 - 3 g$

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$\textcolor{b l u e}{\text{Solving the question}}$

Write as $\frac{1}{2} \left[10 g - 6 + 3 g\right]$

$\frac{1}{2} \left[13 g - 6\right]$

$\frac{13}{2} g - 3$