How do you solve #1/2(4x+6)=1/3(9x-24)#?

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Answer 1 · 2016-11-19T02:15:12

#x = 11#

Step 1) Multiply out the terms within parenthesis:

#(1/2 * 4x) + (1/2 * 6) = (1/3 * 9x) - (1/3 * 24)#

#2x + 3 = 3x - 8#

Step 2) Solve for #x# while keeping the equation balanced:

#2x + 3 - 2x + 8 = 3x - 8 - 2x + 8#

#3 + 8 = 3x - 2x#

#11 = x#