How do you solve #1/2(x-3)+(3/2-x)=5 x#?

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Answer 1 · 2016-05-07T10:09:52

See explanation below: I do not believe this equation can be solved.

I'll just work through the steps in order, explaining what I'm doing at each step:

#1/2(x-3)+(3/2-x)=5x#

Expand the brackets:

#x/2-3/2+3/2-x=5x#

Collect like terms: the constants (terms without x in them) cancel out:

#x/2-x=5x#

This is a problem, because we now have only terms in x, no constant terms to equate them to.

I don't believe this equation can be solved to find a value for x.