How do you solve #1/2(x-4)-(5+x) = 0#?

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Answer 1 · 2018-07-16T12:10:57

#x=-14#

Multilying the given equation by #2#

#x-4-2(5+x)=0#
expanding

#x-4-10-2x=0#

combining like terms

#-14-x=0#

adding #x#

so we get

#x=-14#