How do you solve # 1/3 + 2/(3y) = 1/y^2#?
Let's start with the original question:
Now let's get both fractions on the left side to have a common denominator to make it easier for our calculations. We see that
Now let's combine the two fractions to create this:
Now we can go ahead and use cross multiplication to help simplify the equation, turning it into this:
Then we use the distributive property to simplify the left side of the equation:
two numbers: the sum is -2, the product is
you shall not divide by zero.