How do you solve #1/3 abs(2c-5)+3=7 #?

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Answer 1 · 2016-07-23T06:11:01

#c=-7/2 and c=17/2#

The given equation is equivalent to the following:

#1/3|2c-5|=-3+7#

#1/3|2c-5|=4#

#|2c-5|=12#

#2c-5=+-12#

#2c=5+-12#

#c=(5+-12)/2#

#c=-7/2 and c=17/2#