# How do you solve 1/3 abs(2c-5)+3=7 ?

Jul 23, 2016

$c = - \frac{7}{2} \mathmr{and} c = \frac{17}{2}$

#### Explanation:

The given equation is equivalent to the following:

$\frac{1}{3} | 2 c - 5 | = - 3 + 7$

$\frac{1}{3} | 2 c - 5 | = 4$

$| 2 c - 5 | = 12$

$2 c - 5 = \pm 12$

$2 c = 5 \pm 12$

$c = \frac{5 \pm 12}{2}$

$c = - \frac{7}{2} \mathmr{and} c = \frac{17}{2}$