How do you solve 1/3(c+1)=1/6(3c-5)?

May 24, 2017

$c = 7$

Explanation:

Step 1. Multiply both sides of this equation by 6, to get rid of the fractions

$6 \times \frac{1}{3} \left(c + 1\right) = 6 \times \frac{1}{6} \left(3 c - 5\right)$

$2 \left(c + 1\right) = 3 c - 5$

Step 2. Multiply 2 through on left hand side

$2 c + 2 = 3 c - 5$

Step 3. Add 5 to both sides

$2 c + 7 = 3 c$

Step 4. Subtract $2 c$ from both sides

$7 = c$ or $c = 7$