How do you solve 1/32^(2x)=64?

1 Answer
Apr 25, 2016

x=-3/5

Explanation:

Using properties of exponents we are going to rewrite everything in terms of base 2.

1/(32^2)^x=64

1/((2^5)^2)^x=64

1/2^(10x)=2^6

2^(-10x)=2^6

Since we are now in the same base we can do the following

-10x=6

x=6/-10=-3/5