# How do you solve 1/3y + 2/5 - 2/3y= 4/8?

Nov 5, 2014

$\frac{1}{3} y + \frac{2}{5} - \frac{2}{3} y = \frac{4}{8}$

by $\frac{4}{8} = \frac{1}{2}$,

$\implies \frac{1}{3} y + \frac{2}{5} - \frac{2}{3} y = \frac{1}{2}$

by subtracting $\frac{2}{5}$,

$\implies \frac{1}{3} y - \frac{2}{3} y = \frac{1}{2} - \frac{2}{5}$

by finding the common denominator (10),

$\implies - \frac{1}{3} y = \frac{5}{10} - \frac{4}{10} = \frac{5 - 4}{10} = \frac{1}{10}$

by multiply by $- 3$,

$\implies y = - \frac{3}{10}$.

I hope that this was helpful.