How do you solve #1/3y+5=9#?

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Answer 1 · 2017-08-23T22:16:32

See a solution process below:

Step 1) Subtract #color(red)(5)# from each side of the equation to isolate the #y# term while keeping the equation balanced:

#1/3y + 5 - color(red)(5) = 9 - color(red)(5)#

#1/3y + 0 = 4#

#1/3y = 4#

Step 2) Multiply each side of the equation by #color(red)(3)# to solve for #y# while keeping the equation balanced:

#color(red)(3) xx 1/3y = color(red)(3) xx 4#

#color(red)(3)/3y = 12#

#1y = 12#

#y = 12#