How do you solve #1+(3y)/(y-2)= 6/(y-2)# and find any extraneous solutions?
There is only one solution,
However this is an extraneous solution because it makes the denominators equal to
Hence there is no solution.
Both the denominators are the same, so re-arrange the fraction terms on the same side:
However, this solution is not valid because it makes the denominators equal to