How do you solve #1 /( 4 x + 2) = 5# and find any extraneous solutions?

1 Answer
Jan 18, 2017

Answer:

#x=-9/20#

Explanation:

Eliminate the fraction on the left side of the equation by multiplying both sides by (4x +2) the denominator of the fraction.

#rArrcancel((4x+2))xx1/cancel((4x+2))=5(4x+2)#

#rArr1=20x+10#

subtract 10 from both sides.

#1-10=20xcancel(+10)cancel(-10)#

#rArr20x=-9#

To solve for x, divide both sides by 20

#(cancel(20) x)/cancel(20)=(-9)/20#

#rArrx=-9/20" is the only solution"#