How do you solve #1 /( 4 x + 2) = 5# and find any extraneous solutions?
1 Answer
Jan 18, 2017
Explanation:
Eliminate the fraction on the left side of the equation by multiplying both sides by (4x +2) the denominator of the fraction.
#rArrcancel((4x+2))xx1/cancel((4x+2))=5(4x+2)#
#rArr1=20x+10# subtract 10 from both sides.
#1-10=20xcancel(+10)cancel(-10)#
#rArr20x=-9# To solve for x, divide both sides by 20
#(cancel(20) x)/cancel(20)=(-9)/20#
#rArrx=-9/20" is the only solution"#
