How do you solve #1/4(x-3)=-2#?

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Answer 1 · 2018-03-19T02:09:13

#x=-5#

1.You first multiply the #1/4# to #(x-3)#

You should get #x/4# - #3/4# = #2#

2.After that you add #3/4# to #2# because you are trying to isolate the variable, #x#.

You should get #x/4 = -5/4#

3.You then multiply #4# on each side of the equation to cancel out

the denominator for #x/4#

You should get #x=-5#