How do you solve #1/4t-1/6=-4/9#?

2 Answers
Jun 29, 2017

Answer:

#t = -20/18#

Explanation:

First put the #1/6# on the other side so that #t# is on its own.

#1/4 t = -4/9 + 1/6#

Find a common denominator, 18, so that the two fractions can be added together.

#1/4 t = (-8 + 3)/18 -> -5/18#

#t/4 = -5/18#

#18t = -20#

#t = -20/18#

Jun 29, 2017

Answer:

#t=-10/9#

Explanation:

First, bring the constants (a number on its own) to the right-hand side in order to isolate #t#. We end up with #t# on the left-hand side and the constants on the right-hand side. If we bring #-1/6# over, we have to do the inverse operation. In this case, we do
addition like this:

#t/4-1/6=-1/9#
#t/4=-1/9+1/6#
#t/4=-5/18#

We can then cross multiply which is when we multiply the denominators and numerators that are diagonal to each other, like this:

#t*18=-5*4#
#18t=-20#

All we have to do is to divide each side by 18 to get #t# by itself.

#(18t)/18=-20/18#
#t=-10/9#

Hope this helps you, mate.