How do you solve #1/4t + 5 = 3/4t - 2#?

2 Answers
Jul 15, 2015

Answer:

I found: #t=14#

Explanation:

You can collect terms with #t# on the left and get:
#1/4t-3/4t=-2-5#
#(1-3)/4t=-7#
#-2/4t=-7#
#-1/2t=-7#
rearranging:
#t=14#

Jul 15, 2015

Answer:

I would solve it by multiplying all terms (on both sides) by #4# and then perform the normal arithmetic operations to get #t=14#.
(other people might like working with the fractions).

Explanation:

Given #1/4t + 5 = 3/4t -2#

If we multiply all terms by #4# to get rid of the fractions:
#color(white)("XXXX")##t + 20 = 3t -8#

We can add #(8-t)# to both sides
#color(white)("XXXX")##28 = 2t#

Flipping the equation ('cause I like it better that way) and dividing by 2
#color(white)("XXXX")##t =14#