How do you solve #(1/5)^(x-5) = 25^(3x+2)#?

1 Answer
Noah G
Dec 31, 2015

Write everything under the same base to solve efficiently.

Explanation:

Since #(1/n)^x# = #n^-x#

#5^(-x + 5)# = #5^(6x + 4)#

#5^(-7x)# = #5^-1#

x = #1/7#

The solution to your equation is #1/7#.

Hopefully you understand now

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