Question

How do you solve `1.6= log(4x)`?

Answer 1

I found: `x=9.9526` for the log in base `10`.

Explanation:

It depends upon the base, `b`, of your log:
`1.6=log_b(4x)`
normally `b` would be `10` because it can be easily evaluated using a pocket calculator; if your base is different, in the next part, simply use your given value instead of `10`.

Use the definition of log:

`log_bx=a->x=b^a`

so that:
`1.6=log_b(4x)` becomes:
`4x=b^(1.6)`
where, if `b=10`, then;
`x=1/4*10^(1.6)`
`x=9.9526`