Question

How do you solve `1.8^x=(1/32)^(x-2)`?

Answer 1

1.71, nearly.

Explanation:

log (`a^m`) = m log a
Equate logarithms (of any base ) of the expressions, on both the sides.
x log 1.8 = - ( x`-`2) log 32
x = `2log32/(log1.8+log32)`