How do you solve #1/(c-2) + 1/c = 2/(c(c-2))#?

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Answer 1 · 2015-12-15T13:51:37

No solution

Assume that solution exist.

Multiply both sides by #c(c-2)#.

#c+(c-2)=2#

#2c-2=2#

#2c=4#

#c=2#

Upon inspection, there is division by zero in the first fraction.

Hence there are no solution.