# How do you solve # 1/(x^2 -3) = 8/x#?

##### 1 Answer

Apr 21, 2016

#### Explanation:

Multiply both sides by

#x = 8(x^2-3) = 8x^2-24#

Subtract

#8x^2-x-24 = 0#

This is in the form

#x = (-b+-sqrt(b^2-4ac))/(2a)#

#=(1+-sqrt((-1)^2-4(8)(-24)))/(2*8)#

#=1/16+-sqrt(769)/16#