How do you solve #1+(x^2-5x-24)/(3x)=(x-6)/(3x)# and check for extraneous solutions?
1 Answer
Dec 9, 2016
Put on a common denominator.
#(3x + x^2 - 5x - 24)/(3x) = (x- 6)/(3x)#
#x^2 - 2x - 24 = x - 6#
#x^2 - 3x - 18 = 0#
#(x - 6)(x + 3) = 0#
#x = 6 and -3#
The restrictions of the initial equation are
Hopefully this helps!
