# How do you solve #1+(x^2-5x-24)/(3x)=(x-6)/(3x)# and check for extraneous solutions?

##### 1 Answer

Dec 9, 2016

Put on a common denominator.

#(3x + x^2 - 5x - 24)/(3x) = (x- 6)/(3x)#

#x^2 - 2x - 24 = x - 6#

#x^2 - 3x - 18 = 0#

#(x - 6)(x + 3) = 0#

#x = 6 and -3#

The restrictions of the initial equation are

Hopefully this helps!