Question

How do you solve `10+1/3x^2=18`?

Answer 1

`x= +-2sqrt(6)`

Explanation:

`10 + 1/3x^2 = 18`

Subtract 10 from both sides

`1/3x^2 = 8`

Multiply both sides by 3

`x^2 = 24`

Take square root of both sides:

`x = +-sqrt(24) = +-sqrt(4)sqrt(6) = +-2sqrt(6)`