How do you solve $10^{2 - 3 x} = 10^{5 x - 6}$ $10^(2-3x)=10^(5x-6)$ ?

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Answer 1 · 2018-03-22T12:06:24

Follow explanation

$2 - 3 x = 5 x - 6$ $2-3x = 5x-6$

because base is the same.

$2 + 6 = 5 x + 3 x$ $2+6 = 5x+3x$

$8 = 8 x$ $8 = 8x$

$x = 1$ $x=1$

Therefore,

$10^{- 1} = 10^{- 1}$ $10^-1 = 10^-1$

How do you solve 10^(2-3x)=10^(5x-6)102−3x=105x−610^(2-3x)=10^(5x-6)?