# How do you solve #10/(3x)-8=2/x# and find any extraneous solutions?

##### 1 Answer

Jul 9, 2016

#x=1/6#

#### Explanation:

#10/(3x)-8=2/x# Multiply both sides by#x#

#(10x)/(3x)-8x=2#

#(10 cancelx)/(3 cancelx)-8x=2# Multiply both sides by#3#

#(10xx3)/3-((8x)xx3)=2xx3#

#(10xxcancel3)/cancel3-24x=6#

#10-24x=6#

#-24x=6-10=-4#

#x=(-4)/(-24)=1/6#