How do you solve #(10+ 4) \div ( 26- 19)#?

1 Answer
Shwetank Mauria
Sep 24, 2016

#(10+4)-:(26-19)=2#

Explanation:

We have to solve operations in the order of PEMDAS i.e. first Parentheses, then Exponents, then multiplication, division, addition and subtraction in that order. Hence, we do in this order.

#(10+4)-:(26-19)#

= #14-:7# - we have solved parentheses first

= #2# - there are no exponents / multiplication operations involved.

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