Question

How do you solve `10/(n^2-1)+(2n-5)/(n-1)=(2n+5)/(n+1)`?

Answer 1

`n = 5/3`

Explanation:

Note that `n^2 - 1 = (n + 1)(n - 1)`.

`10/((n + 1)(n - 1)) + ((2n - 5)(n + 1))/((n + 1)(n - 1)) = ((2n + 5)(n - 1))/((n - 1)(n + 1))`

`10 + 2n^2 - 5n + 2n - 5 = 2n^2 + 5n - 2n - 5`

`10 = 6n`

`5/3 = n`

Hopefully this helps!